2k^2-12k+18=0

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Solution for 2k^2-12k+18=0 equation: 



2k^2-12k+18=0

a = 2; b = -12; c = +18;
Δ = b2-4ac
Δ = -122-4·2·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{12}{4}=3$

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